Sederhanakan
2 log 32 + 3 log 27 + 5 log 125 - 7 log 49![]()
2 log 32 + 3 log 27 + 5 log 125 - 7 log 49
Penjelasan dengan langkah-langkah:
2 log 32 + 3 log 27 + 5 log 125 - 7 log 49
= 2 log 2⁵ + 3 log 3³ + 5 log 5³ - 7 log 7²
= 5. 2 log 2 + 3. 3 log 3 + 3. 5 log 5 - 2. 7 log 7
= 5 (1) + 3 (1) + 3 (1) - 2 (1)
= 5 + 3 + 3 - 2
= 8 + 3 -2
= 11 - 2
= 9
Sifat logaritma
a log b^n = n × a log b
a log a = 1
semoga membantuu yaa.
[answer.2.content]
