jika dirasionalkan pecahan 2per √6-√2 menjadi
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Jawaban:
[tex] \frac{1}{2} ( \sqrt{6} + \sqrt{2} )[/tex]
Penjelasan dengan langkah-langkah:
[tex] \frac{2}{ \sqrt{6} - \sqrt{2} } \times \frac{ \sqrt{6} + \sqrt{2} }{ \sqrt{6} + \sqrt{2} } [/tex]
[tex] \frac{2 \sqrt{6} + 2 \sqrt{2} }{6 + \sqrt{12 } - \sqrt{12} - 2 } [/tex]
[tex] \frac{2( \sqrt{6} + \sqrt{2}) }{4} [/tex]
[tex] \frac{1}{2} ( \sqrt{6} + \sqrt{2} )[/tex]
atau
[tex] \frac{1}{2} ( \sqrt{3} \times \sqrt{2} ) + \sqrt{2} [/tex]
[tex] \frac{1}{2} \sqrt{2} ( \sqrt{3} + 1)[/tex]
[answer.2.content]
